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关于SQLServer2005的学习笔记——生日问题

原创 Linux操作系统 作者:bq_wang 时间:2010-02-21 15:35:48 0 删除 编辑
Normal 0 7.8 磅 0 2 false false false EN-US ZH-CN X-NONE生日问题是个看似简单逻辑上却又比较复杂的小问题

主要的逻辑难点第一个是关于闰月尾天的计算,第二个是判断本年度生日是否已过

本文给出了三种解决办法,

第一种是最常用的解决办法,即常用的SQL语法,不过看起来比较复杂,适合环境为SQLServer2000以上

第二种是采用函数的方法,把对日期的逻辑处理放到函数中,调用起来会简约一下,适合环境为SQLServer2000以上

第三种是采用CTE的方法,用CTE来封装判断逻辑,适合环境为SQLServer2005以上

--创建表和数据

CREATE TABLE employees

(

  name     VARCHAR(50),

  birthday DATETIME

)

INSERT INTO employees VALUES('WBQ','1948-12-08');

INSERT INTO employees VALUES('CZH','1952-02-19');

INSERT INTO employees VALUES('LB','1963-08-30');

INSERT INTO employees VALUES('YLL','1937-09-19');

INSERT INTO employees VALUES('YGQ','1955-03-04');

INSERT INTO employees VALUES('CHH','1963-07-02');

INSERT INTO employees VALUES('SWG','1960-05-29');

INSERT INTO employees VALUES('HW','1958-01-01');

INSERT INTO employees VALUES('YY','1972-02-29');

INSERT INTO employees VALUES('LM','1999-02-08');

INSERT INTO employees VALUES('ZY','1972-06-09');

INSERT INTO employees VALUES('WZH','1999-02-28');

SELECT name,birthday FROM employees

 

--普通的SQL实现

SELECT

  name,

  birthday,

  GETDATE() getdate,

  CONVERT(VARCHAR(10),GETDATE(),120) todayVarchar,

  CONVERT(DATETIME,CONVERT(VARCHAR(10),GETDATE(),120)) todayDateTime,

  DATEDIFF(YY,birthday,GETDATE()) DateBetween,

  DATEADD(YY,DATEDIFF(YY,birthday,GETDATE()),birthday) ThisBirthday,

  DATEADD(YY,DATEDIFF(YY,birthday,GETDATE())+1,birthday) NextBirthday,

  CASE WHEN CONVERT(DATETIME,CONVERT(VARCHAR(10),GETDATE(),120))>DATEADD(YY,DATEDIFF(YY,birthday,GETDATE()),birthday)

       THEN DATEADD(YY,DATEDIFF(YY,birthday,GETDATE())+1,birthday)

       ELSE DATEADD(YY,DATEDIFF(YY,birthday,GETDATE()),birthday)

  END newBirthdayStandard,

  CASE WHEN CONVERT(DATETIME,CONVERT(VARCHAR(10),GETDATE(),120))>DATEADD(YY,DATEDIFF(YY,birthday,GETDATE()),birthday)       

       THEN DATEADD(YY,DATEDIFF(YY,birthday,GETDATE())+1,birthday)+

            CASE WHEN DAY(birthday)=29 AND DAY(DATEADD(YY,DATEDIFF(YY,birthday,GETDATE())+1,birthday))=28 THEN 1 ELSE 0 END

       ELSE DATEADD(YY,DATEDIFF(YY,birthday,GETDATE()),birthday) +

            CASE WHEN DAY(birthday)=29 AND DAY(DATEADD(YY,DATEDIFF(YY,birthday,GETDATE()),birthday))=28 THEN 1 ELSE 0 END

  END newBirthdayForeign 

FROM employees

 

--使用函数来实现

CREATE FUNCTION GetBirthday(@birthday DATETIME,@flag INT)

RETURNS DATETIME

AS

BEGIN

  DECLARE @BirthdayRet DATETIME,@BirthdayThis DATETIME,@BirthdayNext DATETIME,@today DATETIME,@dateBetween INT

  SET @today=CONVERT(DATETIME,CONVERT(VARCHAR(10),GETDATE(),120))

  SET @dateBetween=DATEDIFF(YY,@birthday,GETDATE())

  SET @BirthdayThis=DATEADD(YY,@DateBetween,@birthday)    

  SET @BirthdayNext=DATEADD(YY,@DateBetween+1,@birthday)

  IF @flag=1 --2月29日的生日计算为2月28日

  BEGIN

    IF @today>@BirthdayThis

       SET @BirthdayRet=@BirthdayNext

    ELSE

       SET @BirthdayRet=@BirthdayThis

  END

  ELSE       --2月29日的生日计算为3月1日

  BEGIN

    IF @today>@BirthdayThis

            IF DAY(@birthday)=29 AND DAY(@BirthdayNext)=28

          SET @BirthdayRet=@BirthdayNext+1

       ELSE

          SET @BirthdayRet=@BirthdayNext

    ELSE

            IF DAY(@birthday)=29 AND DAY(@BirthdayThis)=28

          SET @BirthdayRet=@BirthdayThis+1

       ELSE

          SET @BirthdayRet=@BirthdayThis  END    

  RETURN @BirthdayRet

END

 

SELECT name,birthday,dbo.GetBirthday(birthday,0),dbo.GetBirthday(birthday,1) FROM employees

 

--通过CTE来实现

WITH DateBetween AS

(

  SELECT  

    name,

    birthday,

    GETDATE() getdate,

    CONVERT(VARCHAR(10),GETDATE(),120) todayVarchar,

    CONVERT(DATETIME,CONVERT(VARCHAR(10),GETDATE(),120)) todayDateTime,

    DATEDIFF(YY,birthday,GETDATE()) DateBetween

  FROM employees

),

DateBirthdayThisAndNext AS

(

  SELECT

    name,birthday,getdate,todaydatetime,datebetween,

    DATEADD(YY,DateBetween,birthday) AS DateCur,

    DATEADD(YY,DateBetween+1,birthday) AS DateNext

  FROM DateBetween

),

DateBirthdayThisAndNextForeign AS

(

  SELECT

    name,birthday,todaydatetime,

    DateCur,DateNext,

    DateCur+CASE WHEN DAY(birthday)=29 AND DAY(DateCur)=28 THEN 1 ELSE 0 END AS DateCurForeign,

    DateNext+CASE WHEN DAY(birthday)=29 AND DAY(DateNext)=28 THEN 1 ELSE 0 END AS DateNextForeign

  FROM DateBirthdayThisAndNext

),

DateBirthday AS

(

  SELECT

    name,birthday,

    CASE WHEN DateCurForeign>=todaydatetime THEN DateCurForeign ELSE DateNextForeign END AS birthDayForeign,

    CASE WHEN DateCur>=todaydatetime THEN DateCur ELSE DateNext END AS birthDayStandard

  FROM DateBirthdayThisAndNextForeign

)

SELECT name,birthday,birthDayForeign,birthDayStandard FROM DateBirthday

 

 

来自 “ ITPUB博客 ” ,链接:https://blog.itpub.net/6517/viewspace-627396/ ,如需转载,请注明出处,否则将追究法律责任。

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