●連續質數2.3.5.7.11.13.17.19的規律●(12)
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主要表達：8連續質數的4解4連環。
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《―》上期答案
(a+c+h)+-×÷(b+d+e+f+g)
=
(b+d+e+f+g+h)+-×÷(a+c)
=
(b+h)+-×÷(a+c+d+e+f+g)
=
(a+c+d+e+f+g+h)+-×÷(b)
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**解一：a= -2, b=3, c=5, d=7, e= -11, f= -13, g=17, h=19**
※※※
(-2+5+19)+-×÷(+3+7-11-13+17)
=
(+3+7-11-13+17+19)+-×÷(-2+5)
=
(+3+19)+-×÷(-2+5+7-11-13+17)
=
(-2+5+7-11-13+17+19)+-×÷(+3)
※※※
(22)+-×÷(3)
=
(22)+-×÷(3)
=
(22)+-×÷(3)
=
(22)+-×÷(3)
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**解二：a= -2, b=3, c=5, d= -7, e=11, f=13, g= -17, h=19**
※※※
(-2+5+19)+-×÷(+3-7+11+13-17)
=
(+3-7+11+13-17+19)+-×÷(-2+5)
=
(+3+19)+-×÷(-2+5-7+11+13-17)
=
(-2+5-7+11+13-17+19)+-×÷(+3)
※※※
(22)+-×÷(3)
=
(22)+-×÷(3)
=
(22)+-×÷(3)
=
(22)+-×÷(3)
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**解三： a=2 ,b= -3, c= -5, d=7, e= -11, f= -13, g=17, h=19**
※※※
(+2-5+19)+-×÷(-3+7-11-13+17)
=
(-3+7-11-13+17+19)+-×÷(+2-5)
=
(-3+19)+-×÷(+2-5+7-11-13+17)
=
(+2-5+7-11-13+17+19)+-×÷(-3)
※※※
(16)+-×÷(-3)
=
(16)+-×÷(-3)
=
(16)+-×÷(-3)
=
(16)+-×÷(-3)
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**解四：a=2, b= -3, c= -5, d= -7, e=11, f=13, g= -17, h=19**
※※※
(+2-5+19)+-×÷(-3-7+11+13-17)
=
(-3-7+11+13-17+19)+-×÷(+2-5)
=
(-3+19)+-×÷(+2-5-7+11+13-17)
=
(+2-5-7+11+13-17+19)+-×÷(-3)
※※※
(16)+-×÷(-3)
=
(16)+-×÷(-3)
=
(16)+-×÷(-3)
=
(16)+-×÷(-3)
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《二》今期謎題
**a=?2, b=?3, c=?5, d=?7, e=?11, f=?13, g=?17, h=?19**
※※※
(a+d+e)+-×÷(b+c+f+g+h)
=
(b+c+f+g)+-×÷(a+d+e+h)
=
(b+c+d+e)+-×÷(a+f+g-h)
=
(a+f+g)+-×÷(b+c+d+e+h)
※※※
或者改變一些加號變減號，令三連環成立；
**?2，?3，?5，?7，?11，?13，?17，?19**
※※※
(+2+7+11)+-×÷(+3+5+13+17+19)
=
(+3+5+13+17)+-×÷(+2+7+11+19)
=
(+3+5+7+11)+-×÷(+2+13+17+19)
=
(+2+13+17)+-×÷(+3+5+7+11+19)
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完

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●連續質數2.3.5.7.11.13.17.19的規律●(12)

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