(0.7*(5-1))=3.8 CRN = CEIL(3.8)=4 FRN = FLOOR(3.8)=3 （4 - 3.8）* 4800 + (3.8 - 3) * 6000 = 5760SELECT last_name, salary, department_id, PERCENTILE_CONT(0.7) WITHIN GROUP (ORDER BY salary) OVER (PARTITION BY department_id) "Percentile_Cont", PERCENT_RANK() OVER (PARTITION BY department_id ORDER BY salary) "Percent_Rank" FROM employees WHERE department_id IN (30, 60);LAST_NAME SALARY DEPARTMENT_ID Percentile_Cont Percent_Rank------------------------- ---------- ------------- --------------- ------------Colmenares 2500 30 3000 0Himuro 2600 30 3000 0.2Tobias 2800 30 3000 0.4Baida 2900 30 3000 0.6Khoo 3100 30 3000 0.8Raphaely 11000 30 3000 1Lorentz 4200 60 5760 0Austin 4800 60 5760 0.25Pataballa 4800 60 5760 0.25Ernst 6000 60 5760 0.75Hunold 9000 60 5760 1

PERCENTILE_DISC 功能描述：返回一个与输入的分布百分比值相对应的数据值，分布百分比的计算方法见函数CUME_DIST，如果没有正好对应的数据值，就取大于该分布值的下一个值。注意：本函数与PERCENTILE_CONT的区别在找不到对应的分布值时返回的替代值的计算方法不同

SAMPLE：下例中0.7的分布值在部门30中没有对应的Cume_Dist值，所以就取下一个分布值0.83333333所对应的SALARY来替代SELECT last_name, salary, department_id, PERCENTILE_DISC(0.7) WITHIN GROUP (ORDER BY salary ) OVER (PARTITION BY department_id) "Percentile_Disc", CUME_DIST() OVER (PARTITION BY department_id ORDER BY salary) "Cume_Dist" FROM employees WHERE department_id in (30, 60);LAST_NAME SALARY DEPARTMENT_ID Percentile_Disc Cume_Dist------------------------- ---------- ------------- --------------- ----------Colmenares 2500 30 3100 .166666667Himuro 2600 30 3100 .333333333Tobias 2800 30 3100 .5Baida 2900 30 3100 .666666667Khoo 3100 30 3100 .833333333Raphaely 11000 30 3100 1Lorentz 4200 60 6000 .2Austin 4800 60 6000 .6Pataballa 4800 60 6000 .6Ernst 6000 60 6000 .8Hunold 9000 60 6000 1

RANK 功能描述：根据ORDER BY子句中表达式的值，从查询返回的每一行，计算它们与其它行的相对位置。组内的数据按

ORDER BY子句排序，然后给每一行赋一个号，从而形成一个序列，该序列从1开始，往后累加。每次ORDER BY表达式的值发生变化时，该序列也随之增加。有同样值的行得到同样的数字序号（认为null时相等的）。然而，如果两行的确得到同样的排序，则序数将随后跳跃。若两行序数为1，则没有序数2，序列将给组中的下一行分配值3，DENSE_RANK则没有任何跳跃。

SAMPLE：下例中计算每个员工按部门分区再按薪水排序，依次出现的序列号（注意与DENSE_RANK函数的区别）SELECT d.department_id , e.last_name, e.salary, RANK() OVER (PARTITION BY e.department_id ORDER BY e.salary) as drank FROM employees e, departments dWHERE e.department_id = d.department_id AND d.department_id IN (@#60@#, @#90@#);DEPARTMENT_ID LAST_NAME SALARY DRANK------------- ------------------------- ---------- ---------- 60 Lorentz 4200 1 60 Austin 4800 2 60 Pataballa 4800 2 60 Ernst 6000 4 60 Hunold 9000 5 90 Kochhar 17000 1 90 De Haan 17000 1 90 King 24000 3

RATIO_TO_REPORT 功能描述：该函数计算expression/(sum(expression))的值，它给出相对于总数的百分比，即当前行对sum(expression)的贡献。

SAMPLE：下例计算每个员工的工资占该类员工总工资的百分比SELECT last_name, salary, RATIO_TO_REPORT(salary) OVER () AS rr FROM employeesWHERE job_id = @#PU_CLERK@#;LAST_NAME SALARY RR------------------------- ---------- ----------Khoo 3100 .223021583Baida 2900 .208633094Tobias 2800 .201438849Himuro 2600 .18705036Colmenares 2500 .179856115