1.使用date命令的%U参数取得当前是全年的第几周
man date中对%U参数的描述
%U     week number of year, with Sunday as first day of week (00..53)
[root@RHEL53 ~]# date +%U
09

2.使用expr的取模运算符%对周数取模2，结果为1表示是单周，结果为0表示是双周
[root@RHEL53 ~]# date
Tue Mar 3 12:33:20 CST 2009
[root@RHEL53 ~]# date +%U
09
[root@RHEL53 ~]# date
Tue Mar 3 12:36:05 CST 2009
[root@RHEL53 ~]# ODD_EVEN=$(expr `date +%U` % 2)
[root@RHEL53 ~]# echo $ODD_EVEN
1

3.使用if条件语句进行判断，实操：
[root@RHEL53 ~]# sh test.sh
This week is singular week.
[root@RHEL53 ~]# cat test.sh
ODD_EVEN=$(expr `date +%U` % 2)
if [ $ODD_EVEN -eq "0" ]
then
        echo This week is dual week.
else
        echo This week is singular week.
fi
[root@RHEL53 ~]# date
Tue Mar 3 12:36:30 CST 2009
[root@RHEL53 ~]# sh test.sh
This week is singular week.

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【Shell】使用date,expr,%,if等判断单双周

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