如何获取反向的 sys_connect_by_path()结果
SELECT path
FROM (SELECT uuid,
trim(both '>' from
trim(both '-' from SYS_CONNECT_BY_PATH(K . NAME, '-->'))) as path
FROM region K
START WITH K.uuid =
(SELECT uuid
FROM (SELECT uuid, pid
FROM region
START WITH uuid = '610204004'
CONNECT BY uuid = PRIOR pid)
WHERE pid IS NULL)
CONNECT BY PRIOR K.uuid = K.pid)
WHERE uuid = '610204004';
reverse('a-->b-->c')
=>
'c>--b>--a
不能实现；并且如果是汉字乱码
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