看看polling方式下系统调用情况
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SQL> SELECT
2 VALUE_KSPVLD_VALUES
3 FROM
4 X$KSPVLD_VALUES
5 WHERE
6 LOWER(NAME_KSPVLD_VALUES) ='_use_adaptive_log_file_sync';
VALUE_KSPVLD_VALUES
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TRUE
FALSE
POLLING_ONLY
_use_adaptive_log_file_sync有三个值,如果指定为POLLING_ONLY, log file sync就是纯粹的polling方式
1.修改参数
alter system set "_use_adaptive_log_file_sync"=POLLING_ONLY;
2.suspend lgwr进程
SQL> oradebug setospid 21008
Oracle pid: 17, Unix process pid: 21008, image: oracle@node1 (LGWR)
SQL> oradebug suspend
Statement processed.
3.提交事物
SQL> insert into a values(123);
1 row created.
SQL> commit;
这里hang了
本process的spid是21083
4.strace一下
strace -rp 21083 | more
0.001526 nanosleep({0, 456000}, {1, 202328316}) = 0
0.000785 nanosleep({0, 456000}, {1, 202328316}) = 0
0.001589 nanosleep({0, 456000}, {1, 202328316}) = 0
0.000923 nanosleep({0, 456000}, {1, 202328316}) = 0
0.001608 nanosleep({0, 456000}, {1, 202328316}) = 0
0.001090 nanosleep({0, 456000}, {1, 202328316}) = 0
0.003045 nanosleep({0, 456000}, {1, 202328316}) = 0
0.000986 nanosleep({0, 456000}, {1, 202328316}) = 0
0.000888 nanosleep({0, 456000}, {1, 202328316}) = 0
0.000990 nanosleep({0, 456000}, {1, 202328316}) = 0
0.001378 nanosleep({0, 456000}, {1, 202328316}) = 0
0.000792 nanosleep({0, 456000}, {1, 202328316}) = 0
0.000951 nanosleep({0, 456000}, {1, 202328316}) = 0
0.001002 nanosleep({0, 456000}, {1, 202328316}) = 0
0.000901 nanosleep({0, 456000}, {1, 202328316}) = 0
看看21083的cpu情况
PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND
21083 oracle 20 0 1047m 75m 71m S 3.6 3.8 0:28.81 oracle
和传统的post/wait方式已经不能同日而语了