Mysql创建外键约束会自动创建一个索引,但是Oracle不会这样做。
所以Oracle在创建外键之后,一定要手动创建索引。
如果没有在外键上创建索引,会经常遇到如下问题。
1.死锁
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--创建实验表
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create table emp as select * from hr.employees;
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create table dept as select * from hr.departments;
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alter table emp add constraint pk_emp primary key (employee_id);
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alter table dept add constraint pk_dept primary key (department_id);
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alter table emp add constraint fk_emp_dept foreign key (department_id) references dept(department_id) on delete cascade;
如果删除任意一条Emp表的记录,都会导致dept表的所有记录不能删除。
SessionA,删除任意一条Emp表记录,不提交

另一个SessionB,他删除任何dept表的记录,都会被阻塞。

当然,对Dept表的插入和更新不受影响
(假设不更新主键字段)
2.性能下降
查询某个部门的员工信息。
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select employee_id,dept.department_name,first_name
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from dept
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inner join emp
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on emp.department_id=dept.department_id
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where emp.department_id=80;
如果没有索引,则emp表全表扫描

如果外键建立索引,则优化的效果显而易见

下面是Tom给出的脚本,检查外键无索引的表
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COLUMN COLUMNS format a30 word_wrapped
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COLUMN tablename format a15 word_wrapped
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COLUMN constraint_name format a15 word_wrapped
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SELECT TABLE_NAME,
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CONSTRAINT_NAME,
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CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) ||
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NVL2(CNAME3, ',' || CNAME3, NULL) ||
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NVL2(CNAME4, ',' || CNAME4, NULL) ||
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NVL2(CNAME5, ',' || CNAME5, NULL) ||
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NVL2(CNAME6, ',' || CNAME6, NULL) ||
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NVL2(CNAME7, ',' || CNAME7, NULL) ||
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NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS
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FROM (SELECT B.TABLE_NAME,
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B.CONSTRAINT_NAME,
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MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1,
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MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2,
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MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3,
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MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4,
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MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5,
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MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6,
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MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7,
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MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8,
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COUNT(*) COL_CNT
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FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME,
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SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME,
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SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME,
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POSITION
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FROM USER_CONS_COLUMNS) A,
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USER_CONSTRAINTS B
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WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME
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AND B.CONSTRAINT_TYPE = 'R'
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GROUP BY B.TABLE_NAME, B.CONSTRAINT_NAME) CONS
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WHERE COL_CNT > ALL
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(SELECT COUNT(*)
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FROM USER_IND_COLUMNS I
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WHERE I.TABLE_NAME = CONS.TABLE_NAME
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AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5,
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CNAME6, CNAME7, CNAME8)
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AND I.COLUMN_POSITION <= CONS.COL_CNT
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GROUP BY I.INDEX_NAME)
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/
参考:
http://blog.csdn.net/dba_waterbin/article/details/9045483
来自 “ ITPUB博客 ” ,链接:https://blog.itpub.net/29254281/viewspace-1065217/
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