[20210223]bbed itl ktbitflg 2.txt
--//简单探究bbed查看ITL槽的ktbitflg含义.它包含2部分信息占32位,前4位表示提交状态,后12位表示dml的记录数.
1.环境:
SCOTT@book> @ ver1
PORT_STRING VERSION BANNER
------------------------------ -------------- --------------------------------------------------------------------------------
x86_64/Linux 2.4.xx 11.2.0.4.0 Oracle Database 11g Enterprise Edition Release 11.2.0.4.0 - 64bit Production
2.测试:
SCOTT@book> create table t as select rownum id from dual connect by level<=740;
Table created.
--//分析略.
SCOTT@book> select rowid,t.* from t where rownum=1;
ROWID ID
------------------ ----------
AAAWIjAAEAAAA2rAAA 1
SCOTT@book> @ rowid AAAWIjAAEAAAA2rAAA
OBJECT FILE BLOCK ROW ROWID_DBA DBA TEXT
---------- ---------- ---------- ---------- -------------------- -------------------- ----------------------------------------
90659 4 3499 0 0x1000DAB 4,3499 alter system dump datafile 4 block 3499
SCOTT@book> select max(id) from t where rowid <='AAAWIjAAEAAAA2rDDD';
MAX(ID)
------------
657
--//dba=4,3499占657条记录.
SCOTT@book> update t set id=id where id<=600;
600 rows updated.
SCOTT@book> @ xid
XIDUSN_XIDSLOT_XIDSQN
------------------------------
10.22.20803
SCOTT@book> alter system flush buffer_cache;
System altered.
--//保证该块不再数据缓存.
3.通过bbed观察:
BBED> p dba 4,3499 ktbbh.ktbbhitl[1]
struct ktbbhitl[1], 24 bytes @68
struct ktbitxid, 8 bytes @68
ub2 kxidusn @68 0x000a
ub2 kxidslt @70 0x0016
ub4 kxidsqn @72 0x00005143
struct ktbituba, 8 bytes @76
ub4 kubadba @76 0x00c001b8
ub2 kubaseq @80 0x10d2
ub1 kubarec @82 0x06
ub2 ktbitflg @84 0x0258 (NONE)
~~~~~~~~~~~~~~~~~~~~~~ --//我没有提交,而且当前该块已经写盘.
union _ktbitun, 2 bytes @86
sb2 _ktbitfsc @86 0
ub2 _ktbitwrp @86 0x0000
ub4 ktbitbas @88 0x00000000
--//0x0258 = 600条.与操作事务记录数一致,并且没有提交.如果我提交不会修改该块(延迟块清除).而是下次select时修改写上.
--//0x00005143 = 20803 与前面看到xid信息也能对上.
SCOTT@book> commit ;
Commit complete.
SCOTT@book> select rowid,t.* from t where rownum=1;
ROWID ID
------------------ ----------
AAAWIjAAEAAAA2rAAA 1
SCOTT@book> alter system flush buffer_cache;
System altered.
--//再通过bbed观察:
BBED> p dba 4,3499 ktbbh.ktbbhitl[1]
struct ktbbhitl[1], 24 bytes @68
struct ktbitxid, 8 bytes @68
ub2 kxidusn @68 0x000a
ub2 kxidslt @70 0x0016
ub4 kxidsqn @72 0x00005143
struct ktbituba, 8 bytes @76
ub4 kubadba @76 0x00c001b8
ub2 kubaseq @80 0x10d2
ub1 kubarec @82 0x06
ub2 ktbitflg @84 0x8000 (KTBFCOM)
union _ktbitun, 2 bytes @86
sb2 _ktbitfsc @86 3
ub2 _ktbitwrp @86 0x0003
ub4 ktbitbas @88 0x177275ce
--//下次读出时修改该事务槽的ktbitflg,并且清除了lck信息为0.
4.继续:
SCOTT@book> update t set id=id-1 where id<=500;
500 rows updated.
SCOTT@book> alter system checkpoint ;
System altered.
SCOTT@book> @ xid
XIDUSN_XIDSLOT_XIDSQN
------------------------------
10.17.20632
--//bbed观察:
BBED> p dba 4,3499 ktbbh.ktbbhitl[1]
struct ktbbhitl[1], 24 bytes @68
struct ktbitxid, 8 bytes @68
ub2 kxidusn @68 0x0003
ub2 kxidslt @70 0x000b
ub4 kxidsqn @72 0x0000078f
struct ktbituba, 8 bytes @76
ub4 kubadba @76 0x00c00754
ub2 kubaseq @80 0x03cc
ub1 kubarec @82 0x03
ub2 ktbitflg @84 0x8000 (KTBFCOM)
union _ktbitun, 2 bytes @86
sb2 _ktbitfsc @86 3
ub2 _ktbitwrp @86 0x0003
ub4 ktbitbas @88 0x17726fba
--//这个时候才修改该事务槽.
4.继续:
SCOTT@book> update t set id=id where id<=500;
500 rows updated.
SCOTT@book> commit ;
Commit complete.
SCOTT@book> alter system flush buffer_cache;
System altered.
--//bbed观察:
BBED> p dba 4,3499 ktbbh.ktbbhitl[2]
struct ktbbhitl[2], 24 bytes @92
struct ktbitxid, 8 bytes @92
ub2 kxidusn @92 0x000a
ub2 kxidslt @94 0x000f
ub4 kxidsqn @96 0x00005140
struct ktbituba, 8 bytes @100
ub4 kubadba @100 0x00c001bb
ub2 kubaseq @104 0x10d2
ub1 kubarec @106 0x07
ub2 ktbitflg @108 0x21f4 (KTBFUPB)
~~~~~~~~~~~ --//我修改并提交,而且提交时该块还在数据缓存,这样快速提交,修改ktbitflg=0x21f4.(0x1f4= 500)
union _ktbitun, 2 bytes @110
sb2 _ktbitfsc @110 0
ub2 _ktbitwrp @110 0x0000
ub4 ktbitbas @112 0x1772772f
SYS@book> alter system dump datafile 4 block 3499;
System altered.
--//转储信息:
Block header dump: 0x01000dab
Object id on Block? Y
seg/obj: 0x16223 csc: 0x03.177275d8 itc: 3 flg: E typ: 1 - DATA
brn: 0 bdba: 0x1000da8 ver: 0x01 opc: 0
inc: 0 exflg: 0
Itl Xid Uba Flag Lck Scn/Fsc
0x01 0xffff.000.00000000 0x00000000.0000.00 C--- 0 scn 0x0003.177274e5
0x02 0x000a.016.00005143 0x00c001b8.10d2.06 C--- 0 scn 0x0003.177275ce
0x03 0x000a.00f.00005140 0x00c001bb.10d2.07 --U- 500 fsc 0x0000.1772772f
bdba: 0x01000dab
data_block_dump,data header at 0x7f08e9727a7c
--//使用U表示 flag,对应就是0x2.很明显0x8表示提交.
5.现在通过bbed修改观察ktbitflg的情况.
BBED> assign dba 4,3499 ktbbh.ktbbhitl[2].ktbitflg=0x11f4;
Warning: contents of previous BIFILE will be lost. Proceed? (Y/N) y
ub2 ktbitflg @108 0x11f4 (KTBFTAC)
BBED> p dba 4,3499 ktbbh.ktbbhitl[2].ktbitflg
ub2 ktbitflg @108 0x11f4 (KTBFTAC)
BBED> sum apply dba 4,3499
Check value for File 4, Block 3499:
current = 0xd412, required = 0xd412
SYS@book> alter system dump datafile 4 block 3499;
System altered.
--//转储信息:
Block header dump: 0x01000dab
Object id on Block? Y
seg/obj: 0x16223 csc: 0x03.177275d8 itc: 3 flg: E typ: 1 - DATA
brn: 0 bdba: 0x1000da8 ver: 0x01 opc: 0
inc: 0 exflg: 0
Itl Xid Uba Flag Lck Scn/Fsc
0x01 0xffff.000.00000000 0x00000000.0000.00 C--- 0 scn 0x0003.177274e5
0x02 0x000a.016.00005143 0x00c001b8.10d2.06 C--- 0 scn 0x0003.177275ce
0x03 0x000a.00f.00005140 0x00c001bb.10d2.07 ---T 500 fsc 0x0000.1772772f
bdba: 0x01000dab
data_block_dump,data header at 0x7f08e9727a7c
--//T 表示0x1,好像没人看见过这样的标识.
BBED> assign dba 4,3499 ktbbh.ktbbhitl[2].ktbitflg=0x41f4;
ub2 ktbitflg @108 0x41f4 (KTBFIBI)
BBED> sum apply dba 4,3499
Check value for File 4, Block 3499:
current = 0x8412, required = 0x8412
SYS@book> alter system dump datafile 4 block 3499;
System altered.
--//转储信息:
Block header dump: 0x01000dab
Object id on Block? Y
seg/obj: 0x16223 csc: 0x03.177275d8 itc: 3 flg: E typ: 1 - DATA
brn: 0 bdba: 0x1000da8 ver: 0x01 opc: 0
inc: 0 exflg: 0
Itl Xid Uba Flag Lck Scn/Fsc
0x01 0xffff.000.00000000 0x00000000.0000.00 C--- 0 scn 0x0003.177274e5
0x02 0x000a.016.00005143 0x00c001b8.10d2.06 C--- 0 scn 0x0003.177275ce
0x03 0x000a.00f.00005140 0x00c001bb.10d2.07 -B-- 500 fsc 0x0000.1772772f
bdba: 0x01000dab
data_block_dump,data header at 0x7f08e9727a7c
--//B 表示0x4,好像也没人看见过这样的标识.
BBED> assign dba 4,3499 ktbbh.ktbbhitl[2].ktbitflg=0xf1f4;
ub2 ktbitflg @108 0xf1f4 (KTBFTAC, KTBFUPB, KTBFIBI, KTBFCOM)
BBED> sum apply dba 4,3499
Check value for File 4, Block 3499:
current = 0x3412, required = 0x3412
BBED> p dba 4,3499 ktbbh.ktbbhitl[2].ktbitflg
ub2 ktbitflg @108 0xf1f4 (KTBFTAC, KTBFUPB, KTBFIBI, KTBFCOM)
SYS@book> alter system dump datafile 4 block 3499;
System altered.
--//转储信息:
Block header dump: 0x01000dab
Object id on Block? Y
seg/obj: 0x16223 csc: 0x03.177275d8 itc: 3 flg: E typ: 1 - DATA
brn: 0 bdba: 0x1000da8 ver: 0x01 opc: 0
inc: 0 exflg: 0
Itl Xid Uba Flag Lck Scn/Fsc
0x01 0xffff.000.00000000 0x00000000.0000.00 C--- 0 scn 0x0003.177274e5
0x02 0x000a.016.00005143 0x00c001b8.10d2.06 C--- 0 scn 0x0003.177275ce
0x03 0x000a.00f.00005140 0x00c001bb.10d2.07 CBUT 0 scn 0x0000.1772772f
bdba: 0x01000dab
data_block_dump,data header at 0x7f08e9727a7c
--//KTBFTAC, KTBFUPB, KTBFIBI, KTBFCOM 分别标识 0x1,0x2,0x4,0x8.
--//比较常见的组合前4位是0x8,0x2,0xa,0x0
--//收尾还原.
BBED> assign dba 4,3499 ktbbh.ktbbhitl[2].ktbitflg=0x21f4;
ub2 ktbitflg @108 0x21f4 (KTBFUPB)
BBED> sum apply dba 4,3499
Check value for File 4, Block 3499:
current = 0xe412, required = 0xe412
BBED> verify
DBVERIFY - Verification starting
FILE = /mnt/ramdisk/book/users01.dbf
BLOCK = 3499
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