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[20200211]zsh的bug.txt
--//上午测试sql文本计算full_hash_value,sql _id,hash_value,发现我以前写的脚本报错。
1.环境
$ head -1 /etc/issue
Oracle Linux Server release 5.9
$ zsh --version
zsh 4.2.6 (x86_64-redhat-linux-gnu)
--//脚本如下,使用zsh的目的是可以直接现实16进制转32进制,写法像这样echo $(( [##32]16#$v2 )。至少目前bash不行。
$ cat sql_id.zsh
#! /bin/zsh
# calcucate sql_text of full_hash_value(16),hash_value(10),sql_id(32).
odebug=${ODEBUG:-0}
#sql_text=${1}'\0'
sql_text=${1}
v1=$(echo -e -n "$sql_text" | md5sum | sed 's/ -//' | xxd -r -p | od -t x4 | sed -n -e 's/^0\+ //' -e 's/ //gp' | tr 'a-z' 'A-Z')
#v2=${v1:(-16):16}
#v3=${v2:(-8):8}
v2=$(echo "obase=16;ibase=16; $v1 % 10000000000000000" | bc| tr -d '\\\r\n')
v3=$(echo "obase=10;ibase=16; $v1 % 100000000" | bc| tr -d '\\\r\n')
if [ $odebug -eq 1 ] ; then
echo v1=$v1 v2=$v2 v3=$v3
fi
echo "sql_text = $sql_text"
echo "full_hash_value(16) = $v1 "
echo "hash_value(10) = $v3 "
#echo "hash_value(10) = $(( 16#$v3 )) "
#res=$( echo $(( [##32]16#$v2 )) | tr $( echo {0..9} {A..V}| tr -d ' ') $(echo {0..9} {a..z} | tr -d 'eilo ') )
res=$( echo $(( [##32]16#$v2 )) | tr 'ABCDEFGHIJKLMNOPQRSTUV' 'abcdfghjkmnpqrstuvwxyz' )
echo "sql_id(32) = $(printf "%13s" $res | tr ' ' '0')"
echo "sql_id(32) = $(printf "%013s" $res )"
2.测试:
SELECT name
,hash_value
,full_hash_value
,namespace
,child_latch
,property hot_flag
,executions
,invalidations
FROM v$db_object_cache
WHERE name = 'select * from dept where deptno=10';
NAME HASH_VALUE FULL_HASH_VALUE NAMESPACE CHILD_LATCH HOT_FLAG EXECUTIONS INVALIDATIONS
---------------------------------------- ---------- -------------------------------- ---------- ----------- ---------- ---------- -------------
select * from dept where deptno=10 2941143312 5196d0b7fe72e5ea7c59eeb2af4e4910 SQL AREA 0 HOTCOPY11 3 0
select * from dept where deptno=10 2941143312 5196d0b7fe72e5ea7c59eeb2af4e4910 SQL AREA 18704 HOTCOPY11 3 0
select * from dept where deptno=10 911274289 1431c45dbddbb9e74eaa74d53650f131 SQL AREA 0 HOT 8 0
select * from dept where deptno=10 911274289 1431c45dbddbb9e74eaa74d53650f131 SQL AREA 61745 HOT 8 0
select * from dept where deptno=10 3106222595 642c74f9bf38538acec7e363b9253203 SQL AREA 0 HOTCOPY7 1 0
select * from dept where deptno=10 3106222595 642c74f9bf38538acec7e363b9253203 SQL AREA 78339 HOTCOPY7 1 0
$ export ODEBUG=1
$ ./sql_id.zsh 'select * from dept where deptno=10\0.7'
v1=642C74F9BF38538ACEC7E363B9253203 v2=CEC7E363B9253203 v3=3106222595
sql_text = select * from dept where deptno=10.7
full_hash_value(16) = 642C74F9BF38538ACEC7E363B9253203
hash_value(10) = 3106222595
./sql_id.zsh:1: number truncated after 15 digits: CEC7E363B9253203
sql_id(32) = 0tv3y6sxt4nt0
sql_id(32) = tv3y6sxt4nt0
--//full_hash_value,hash_value都可以对上。
$ zsh
% echo $(( [##32]16#11 ))
H
% echo $(( [##32]16#AA ))
5A
--//0xaa = 170
% bc
bc 1.06
Copyright 1991-1994, 1997, 1998, 2000 Free Software Foundation, Inc.
This is free software with ABSOLUTELY NO WARRANTY.
For details type `warranty'.
obase=32
170
05 10
--//说明转换正确。
% v2=CEC7E363B9253203
% echo $(( [##32]16#$v2))
zsh: number truncated after 15 digits: CEC7E363B9253203
PR3U6OTP4KP0
% v2=9EC7E363B9253203
% echo $(( [##32]16#$v2))
zsh: number truncated after 15 digits: 9EC7E363B9253203
JR3U6OTP4KP0
% v2=7FFFFFFFFFFFFFFF
% echo $(( [##32]16#$v2))
7VVVVVVVVVVVV
% v2=8000000000000000
% echo $(( [##32]16#$v2))
zsh: number truncated after 15 digits: 8000000000000000
G00000000000
--//计算是丢弃了后面的0.
% v2=800000000000000
% echo $(( [##32]16#$v2))
G00000000000
--//估计操作数太大,操作范围了。
3.在cygwin下测试:
$ zsh --version
zsh 5.5.1 (x86_64-unknown-cygwin)
$ ./sql_id.zsh 'select * from dept where deptno=10\0.7'
sql_text = select * from dept where deptno=10.7
full_hash_value(16) = 642C74F9BF38538ACEC7E363B9253203
hash_value(10) = 3106222595
./sql_id.zsh:25: number truncated after 15 digits: CEC7E363B9253203
sql_id(32) = 0tv3y6sxt4nt0
sql_id(32) = tv3y6sxt4nt0
--//问题一样。看来bash与zsh一样,运算的数值不能太大,也不能称为bug^_^。
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