INSERT INTO table_name(col1, col2, ...)
VALUES (val1, val2, ...);
INSERT INTO employee(emp_id, emp_name, sex, dept_id, manager, hire_date, job_id, salary, bonus, email)
VALUES ( 26, '张三', '男', 5, 18, '2019-12-25', 10, 6000, NULL, 'zhangsan@shuguo.com');
INSERT INTO employee
VALUES ( 26, '张三', '男', 5, 18, '2019-12-25', 10, 6000, NULL, 'zhangsan@shuguo.com');
INSERT INTO employee(emp_id, emp_name, sex, dept_id, manager, hire_date, job_id, salary, bonus, email)
VALUES ( 27, '李四', '男', 5, 18, '2019-12-25', 0, 6000, NULL, 'lisi@shuguo.com');
ERROR 1452 (23000): Cannot add or update a child row: a foreign key constraint fails (`hrdb`.`employee`, CONSTRAINT `fk_emp_job` FOREIGN KEY (`job_id`) REFERENCES `job` (`job_id`))
INSERT INTO employee(emp_id)
VALUES ( 28 );
ERROR 1364 (HY000): Field 'emp_name' doesn't have a default value
INSERT IGNORE INTO employee
VALUES ( 26, '张三', '男', 5, 18, '2019-12-25', 10, 6000, NULL, 'zhangsan@shuguo.com');
Query OK, 0 rows affected, 1 warning (0.00 sec)
show warnings;
+---------+------+-------------------------------------------------+
| Level | Code | Message |
+---------+------+-------------------------------------------------+
| Warning | 1062 | Duplicate entry '26' for key 'employee.PRIMARY' |
+---------+------+-------------------------------------------------+
1 row in set (0.00 sec)
CREATE TABLE t(id int NOT NULL DEFAULT 100);
INSERT INTO t VALUES ();
INSERT INTO t VALUES (default);
SELECT * FROM t;
id |
---|
100|
100|
INSERT INTO table_name
SET col1 = val1,
col2 = val2,
...;
INSERT INTO t
SET id = 1;
DROP TABLE IF EXISTS t;
CREATE TABLE t(id int AUTO_INCREMENT NOT NULL PRIMARY KEY, c1 int);
INSERT INTO t(c1) VALUES (123);
SELECT last_insert_id();
last_insert_id()|
----------------|
1|
INSERT INTO table_name(col1, col2, ...)
VALUES (val11, val12, ...), (val21, val22, ...), ...;
INSERT INTO employee(emp_id, emp_name, sex, dept_id, manager, hire_date, job_id, salary, bonus, email)
VALUES ( 27, '李四', '女', 5, 18, current_date, 10, 6000, NULL, 'lisi@shuguo.com'),
( 28, '王五', '男', 5, 18, current_date, 10, 6500, NULL, 'wangwu@shuguo.com'),
( 29, '赵六', '女', 5, 18, current_date, 10, 6700, NULL, 'zhaoliu@shuguo.com');
SHOW VARIABLES LIKE 'max_allowed_packet';
Variable_name |Value |
------------------|-------|
max_allowed_packet|4194304|
INSERT INTO table_name(col1, col2, ...)
SELECT ...;
CREATE TABLE emp_devp
( emp_id INTEGER NOT NULL PRIMARY KEY
, emp_name VARCHAR(50) NOT NULL
, sex VARCHAR(10) NOT NULL
, dept_id INTEGER NOT NULL
, manager INTEGER
, hire_date DATE NOT NULL
, job_id INTEGER NOT NULL
, salary NUMERIC(8,2) NOT NULL
, bonus NUMERIC(8,2)
, email VARCHAR(100) NOT NULL
) ;
INSERT INTO emp_devp(emp_id, emp_name, sex, dept_id, manager, hire_date, job_id, salary, bonus, email)
SELECT *
FROM employee
WHERE dept_id = (SELECT dept_id FROM department WHERE dept_name = '研发部');
SELECT count(*) FROM emp_devp;
count(*)|
--------|
9|
原文作者:SQL编程思想;如有侵权,请联系管理员删除。