一SQL,每隔n个数据,取其中max,min值
create table tt6 (id int);
begin
for i in 1..10000 loop
insert into tt6 values(i);
end loop;
commit;
end;
select ceil(no/13),max(no),min(no),count(*) from (select rownum as no,id from tt6) group by ceil(no/13) order by 1 asc
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