//167 在有序数组中寻找值为target的两个值的位置(索引+1)
vector twoSum(vector& numbers, int target) {
int i = 0,j=numbers.size()-1;//刚开始我把j=numbers.size(),导致错误
vector result;
while(i twoSum2(vector& numbers, int target) {
int length=numbers.size();
int i = 0;
int mid=0;
for(i; i vec;
vec.push_back(i+1);
vec.push_back(mid+1);
return vec;
}
if( numbers[mid] & height) {
int i=0;
int j=height.size()-1;
int area=0;
while(i 来自 “ ITPUB博客 ” ,链接:https://blog.itpub.net/4614/viewspace-2807877/ ,如需转载,请注明出处,否则将追究法律责任。