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create or replace function comm.F_upper_money(p_num in number default null)
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return nvarchar2 is
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/*Ver:1.0 Created By xsb on 2003-8-18 For:
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将金额数字(单位元)转换为大写(采用从低至高算法)
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数字整数部分不得超过16位,可以是负数。
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Ver:1.1 Modified By xsb on 2003-8-20 For:个位数处理也放在For循环中。
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Ver:1.2 Modified By xsb on 2003-8-22 For:分后不带整字。
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Ver:1.3 Modified By xsb on 2003-8-28 For:完善测试用例。
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测试用例:
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SET HEAD OFF
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SET FEED OFF
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select '无参数时='||f_upper_money() from dual;
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select 'null='||f_upper_money(null) from dual;
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select '0='||f_upper_money(0) from dual;
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select '0.01='||f_upper_money(0.01) from dual;
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select '0.126='||f_upper_money(0.126) from dual;
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select '01.234='||f_upper_money(01.234) from dual;
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select '10='||f_upper_money(10) from dual;
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select '100.1='||f_upper_money(100.1) from dual;
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select '100.01='||f_upper_money(100.01) from dual;
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select '10000='||f_upper_money(10000) from dual;
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select '10012.12='||f_upper_money(10012.12) from dual;
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select '20000020.01='||f_upper_money(20000020.01) from dual;
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select '3040506708.901='||f_upper_money(3040506708.901) from dual;
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select '40005006078.001='||f_upper_money(40005006078.001) from dual;
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select '-123456789.98='||f_upper_money(-123456789.98) from dual;
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select '123456789123456789.89='||f_upper_money(123456789123456789.89) from dual;
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*/
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Result nvarchar2(100); --返回字符串
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num_round nvarchar2(100) := to_char(abs(round(p_num, 2))); --转换数字为小数点后2位的字符(正数)
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num_left nvarchar2(100); --小数点左边的数字
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num_right nvarchar2(2); --小数点右边的数字
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str1 nchar(10) := '零壹贰叁肆伍陆柒捌玖'; --数字大写
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str2 nchar(16) := '元拾佰仟万拾佰仟亿拾佰仟万拾佰仟'; --数字位数(从低至高)
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num_pre number(1) := 1; --前一位上的数字
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num_current number(1); --当前位上的数字
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num_count number := 0; --当前数字位数
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begin
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if p_num is null then
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return null;
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end if; --转换数字为null时返回null
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select to_char(nvl(substr(to_char(num_round),
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1,
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decode(instr(to_char(num_round), '.'),
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0,
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length(num_round),
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instr(to_char(num_round), '.') - 1)),
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0))
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into num_left
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from dual; --取得小数点左边的数字
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select substr(to_char(num_round),
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decode(instr(to_char(num_round), '.'),
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0,
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length(num_round) + 1,
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instr(to_char(num_round), '.') + 1),
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2)
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into num_right
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from dual; --取得小数点右边的数字
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if length(num_left) > 16 then
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return '**********';
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end if; --数字整数部分超过16位时
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--采用从低至高的算法,先处理小数点右边的数字
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if length(num_right) = 2 then
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if to_number(substr(num_right, 1, 1)) = 0 then
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result := '零' ||
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substr(str1, to_number(substr(num_right, 2, 1)) + 1, 1) || '分';
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else
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result := substr(str1, to_number(substr(num_right, 1, 1)) + 1, 1) || '角' ||
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substr(str1, to_number(substr(num_right, 2, 1)) + 1, 1) || '分';
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end if;
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elsif length(num_right) = 1 then
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result := substr(str1, to_number(substr(num_right, 1, 1)) + 1, 1) || '角整';
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else
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result := '整';
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end if;
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--再处理小数点左边的数字
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for i in reverse 1 .. length(num_left) loop
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--(从低至高)
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num_count := num_count + 1; --当前数字位数
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num_current := to_number(substr(num_left, i, 1)); --当前位上的数字
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if num_current > 0 then
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--当前位上数字不为0按正常处理
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result := substr(str1, num_current + 1, 1) ||
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substr(str2, num_count, 1) || result;
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else
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--当前位上数字为0时
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if mod(num_count - 1, 4) = 0 then
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--当前位是元、万或亿时
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result := substr(str2, num_count, 1) || result;
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num_pre := 0; --元、万,亿前不准加零
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end if;
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if num_pre > 0 or length(num_left) = 1 then
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--上一位数字不为0或只有个位时
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result := substr(str1, num_current + 1, 1) || result;
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end if;
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end if;
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num_pre := num_current;
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end loop;
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if p_num < 0 then
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--转换数字是负数时
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result := '负' || result;
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end if;
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return Result;
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exception
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when others then
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raise_application_error(-20001, '数字转换大写出现错误!' || sqlerrm);
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end;
来自 “ ITPUB博客 ” ,链接:https://blog.itpub.net/28878983/viewspace-2133889/
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