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【Oracle】树状结构查询

原创 Linux操作系统 作者:lubinsu 时间:2013-02-10 19:41:11 0 删除 编辑
--oracle中的树状结构查询实际上就是一个中序遍历
--显示以KING为根节点的树,start with定义起始节点
SELECT *
FROM   emp a
START  WITH a.empno = 7839
CONNECT BY PRIOR a.empno = a.mgr;
--置于等号前面,由父节点向子节点方向检索;置于等号后面,则从子节点向父节点方向检索
SELECT *
FROM   emp a
START  WITH a.empno = 7839
CONNECT BY PRIOR a.empno = a.mgr;
--使用伪列level来显示层级关系
SELECT *
FROM   emp a
START  WITH a.empno = 7839
CONNECT BY PRIOR a.empno = a.mgr;

SELECT level, a.*
FROM   emp a
START  WITH a.empno = 7839
CONNECT BY PRIOR a.empno = a.mgr;
--使用函数 sys_connect_by_path 显示全路径
SELECT LEVEL, sys_connect_by_path(a.ename, '/'), a.*
FROM   emp a
START  WITH a.empno = 7839
CONNECT BY PRIOR a.empno = a.mgr;
--where子句只限定单个节点,不影响子其子节点或者父节点
SELECT LEVEL, sys_connect_by_path(a.ename, '/'), a.*
FROM   emp a
WHERE a.empno <> 7369
START  WITH a.empno = 7839
CONNECT BY PRIOR a.empno = a.mgr;
--connect by 子句限定整个以当前节点为起始节点的整个分支
--connect_by_root 可以在列之前显示最高节点的内容
SELECT LEVEL, connect_by_root(a.job),sys_connect_by_path(a.ename, '/'), a.*
FROM   emp a
WHERE a.empno <> 7369
START  WITH a.empno = 7839
CONNECT BY PRIOR a.empno = a.mgr;
--connect_by_isleaf 显示当前行是否叶子节点,1:是;0:否
SELECT LEVEL, connect_by_isleaf,sys_connect_by_path(a.ename, '/'), a.*
FROM   emp a
WHERE a.empno <> 7369
START  WITH a.empno = 7839
CONNECT BY PRIOR a.empno = a.mgr;
--connect_by_iscycle 10g中开始有的新特性,用来判断当前节点是否产生了循环,0:否;1:是
SELECT LEVEL, connect_by_iscycle, connect_by_isleaf,sys_connect_by_path(a.ename, '/'), a.*
FROM   emp a
WHERE a.empno <> 7369
START  WITH a.empno = 7839
CONNECT BY NOCYCLE PRIOR a.empno = a.mgr;

来自 “ ITPUB博客 ” ,链接:https://blog.itpub.net/28313368/viewspace-754072/ ,如需转载,请注明出处,否则将追究法律责任。

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