#!/bin/bash
floor_num=$1
for floor in `seq 1 ${floor_num}`;do
floor_num=$1
for floor in `seq 1 ${floor_num}`;do
for space in `seq $((${floor_num}-${floor})) -1 1`;do
echo -e " \c"
done
for full in `seq 1 $((2*${floor}-1))`;do
echo -e "*\c"
done
echo " "
done
echo -e " \c"
done
for full in `seq 1 $((2*${floor}-1))`;do
echo -e "*\c"
done
echo " "
done
来自 “ ITPUB博客 ” ，链接：https://blog.itpub.net/27181165/viewspace-775843/ ，如需转载，请注明出处，否则将追究法律责任。
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