ITPub博客

首页 > Linux操作系统 > Linux操作系统 > Substr Function

Substr Function

原创 Linux操作系统 作者:perfychi 时间:2012-11-07 16:42:52 0 删除 编辑

Oracle/PLSQL: Substr Function


In Oracle/PLSQL, the substr functions allows you to extract a substring from a string.

The syntax for the substr function is:

substr( string, start_position, [ length ] )

string is the source string.

start_position is the position for extraction. The first position in the string is always 1.

length is optional. It is the number of characters to extract. If this parameter is omitted, substr will return the entire string.


Note:

If start_position is 0, then substr treats start_position as 1 (ie: the first position in the string).

If start_position is a positive number, then substr starts from the beginning of the string.

If start_position is a negative number, then substr starts from the end of the string and counts backwards.

If length is a negative number, then substr will return a NULL value.


For example:

substr('This is a test', 6, 2) would return 'is'
substr('This is a test', 6) would return 'is a test'
substr('TechOnTheNet', 1, 4) would return 'Tech'
substr('TechOnTheNet', -3, 3) would return 'Net'
substr('TechOnTheNet', -6, 3) would return 'The'
substr('TechOnTheNet', -8, 2)

would return 'On'

PL/SQL BOOCK:

variable g_char varchar2(30);
variable g_num number;
declare
v_char varchar2(30);
v_num number;
begin
   v_char := '42 is answer';
   :g_char := v_char;
   :g_num := substr(V_CHAR,1,2);
end;
/
print g_char;
print g_num;

来自 “ ITPUB博客 ” ,链接:https://blog.itpub.net/27042095/viewspace-748581/ ,如需转载,请注明出处,否则将追究法律责任。

上一篇: Oracle instr函数
请登录后发表评论 登录
全部评论

注册时间:2012-06-06

  • 博文量
    484
  • 访问量
    2976213