with a as
(select 'A' opcode from dual union
select 'B' from dual union
select 'C' from dual union
select 'D' from dual union
select 'E' from dual union
select 'F' from dual
),
b as
(select 'A' opcode, 80 score from dual union
select 'B', 70 from dual union
select 'C', 90 from dual
)
select a.opcode,nvl(b.score,0) from a partition by (a.opcode )left join
b
on a.opcode=b.opcode
opcode score
A 80
B 70
C 90
F 0
E 0
D 0
从最后的结果可以看出 表b被补全了。
来自 “ ITPUB博客 ” ,链接:https://blog.itpub.net/25989950/viewspace-702733/ ,如需转载,请注明出处,否则将追究法律责任。