import java.text.DecimalFormat;
import java.text.NumberFormat;
/**
*
* @author Liucheng
*
* @version
* 2010-11-9 上午11:46:12
* 最准确的使用就是小数点之前最多13位,小数点之后不限,当然写多了也没有用
* 总体思路:
*对数字进行分级处理,级长为4
*对分级后的每级分别处理,处理后得到字符串相连
*如:123456=12|3456
*第二级:12=壹拾贰 + “万”
*第一级:3456 =叁千肆百伍拾陆 + “”
*/
public final class RMB {
private double amount = 0.0D;
private static final String NUM = "零壹贰叁肆伍陆柒捌玖";
private static final String UNIT = "仟佰拾个";
private static final String GRADEUNIT = "仟万亿兆";
private static final String DOTUNIT = "角分厘";
private static final int GRADE = 4;
private static final String SIGN = "¥";
private static final NumberFormat nf = new DecimalFormat("#0.###");
/**
* 带参数的构造方法
*
* @param amount
*/
private RMB(double amount) {
this.amount = amount;
}
public static String toBigAmt(double amount) {
nf.setMinimumFractionDigits(3);//小数点后不足的补零
String amt = nf.format(amount);//将double类型的数格式化并转换成字符串,实际上进行了四舍五入
System.out.println(amt);
Double d = new Double(amount);
String dotPart = ""; //取小数位
String intPart = ""; //取整数位
int dotPos;
if ((dotPos = amt.indexOf('.')) != -1) {
intPart = amt.substring(0, dotPos);
dotPart = amt.substring(dotPos + 1);
if(dotPart.length()>4){ //超过4位直接截取
dotPart = dotPart.substring(0,4);
}
} else {
intPart = amt;
}
if (intPart.length() > 16)
throw new java.lang.InternalError("数额太大,无法转换。");
String intBig = intToBig(intPart);
String dotBig = dotToBig(dotPart);
//以下代码稍做修改,现在好多了。
if ((dotBig.length() == 0) && (intBig.length() != 0)) {
return intBig + "元整";
} else if ((dotBig.length() == 0) && (intBig.length() == 0)) {
return intBig + "零元";
} else if ((dotBig.length() != 0) && (intBig.length() != 0)) {
return intBig + "元" + dotBig;
} else {
return dotBig;
}
}
/**
* 用来处理几角几分几厘
* @param dotPart
* @return
*/
private static String dotToBig(String dotPart) {
//得到转换后的大写(小数部分)
String strRet = "";
for (int i = 0; i < dotPart.length() && i < 3; i++) {
int num;
if ((num = Integer.parseInt(dotPart.substring(i, i + 1))) != 0)
strRet += NUM.substring(num, num + 1)
+ DOTUNIT.substring(i, i + 1);
}
return strRet;
}
/**
* 用来处理多少元 ,这个要仔细考虑才行
* @param intPart
* @return
*/
private static String intToBig(String intPart) {
//得到转换后的大写(整数部分)
int grade; //级长
String result = "";
String strTmp = "";
//得到当级长
grade = intPart.length() / GRADE;
//调整级次长度
if (intPart.length() % GRADE != 0)
grade += 1;
//对每级数字处理,先处理最高级,然后再处理低级的
for (int i = grade; i >= 1; i--) {
strTmp = getNowGradeVal(intPart, i);//取得当前级次数字
result += getSubUnit(strTmp);//转换大写
//System.out.println(strTmp+"|"+getSubUnit(strTmp));
result = dropZero(result);//除零 去掉连续的零
//System.out.println("result="+result);
//加级次单位
if (i > 1) //末位不加单位
//单位不能相连续
//注意:连续4个零的时候要特殊处理(wmj修改此bug)
if(getSubUnit(strTmp).equals("零零零零")){
result = result+"零";
}else{
result += GRADEUNIT.substring(i - 1, i);
}
}
return result;
}
private static String getNowGradeVal(String strVal, int grade) {
//得到当前级次的串
String rst;
if (strVal.length() <= grade * GRADE)
rst = strVal.substring(0, strVal.length() - (grade - 1) * GRADE);
else
rst = strVal.substring(strVal.length() - grade * GRADE, strVal
.length()
- (grade - 1) * GRADE);
return rst;
}
private static String getSubUnit(String strVal) {
//数值转换
String rst = "";
for (int i = 0; i < strVal.length(); i++) {
String s = strVal.substring(i, i + 1);
int num = Integer.parseInt(s);
if (num == 0) {
//“零”作特殊处理
if (i != strVal.length()) //转换后数末位不能为零
rst += "零";
} else {
//If IntKey = 1 And i = 2 Then
//“壹拾”作特殊处理
//“壹拾”合理
//Else
rst += NUM.substring(num, num + 1);
//End If
//追加单位
if (i != strVal.length() - 1)//个位不加单位
rst += UNIT.substring(i + 4 - strVal.length(), i + 4
- strVal.length() + 1);
}
}
return rst;
}
/**
*
* @param strVal
* @return
*/
private static String dropZero(String strVal) {
//去除连继的“零”
String strRst;
String strBefore; //前一位置字符
String strNow; //现在位置字符
strBefore = strVal.substring(0, 1);
strRst = strBefore;
for (int i = 1; i < strVal.length(); i++) {
strNow = strVal.substring(i, i + 1);
if (strNow.equals("零") && strBefore.equals("零"))
;//同时为零
else
strRst += strNow;
strBefore = strNow;
}
//末位去零
if (strRst.substring(strRst.length() - 1, strRst.length()).equals("零"))
strRst = strRst.substring(0, strRst.length() - 1);
return strRst;
}
public static void main(String[] args) {
System.out.println(RMB.toBigAmt(1234567.9));
}
}
来自 “ ITPUB博客 ” ,链接:https://blog.itpub.net/23676909/viewspace-695667/
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