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$n = 3;
$t = 100;
$c = 2;
$a = [1,2,3];
$count = 0;
if($n>$c){
for($i=0;$c $total = 0;
$countA = 0;
for($j=0;$countA $total = $total + $a[$j];
$countA = $countA+1;
}
if($total $count = $count +1;
}
}
echo($count);
}else{
echo "data err";
}
来自 “ ITPUB博客 ” ,链接:https://blog.itpub.net/1600/viewspace-2798040/ ,如需转载,请注明出处,否则将追究法律责任。