from requests import
from time import
def gettxturl(url):
try:
r=requests.get(url,timeout=10)
print(r.raise_for_status())
r.encoding=r.apparent_encoding
return r.text
except:
return "爬取失败!"
if name=="main":
url='https://www.baidu.com'
t1=float(time())
for i in range(10):
print(gettxturl(url))
t2=float(time())
print(t2-t1)
为啥是爬取失败?格式问题可以忽略
来自 “ ITPUB博客 ” ,链接:https://blog.itpub.net/1427/viewspace-3132079/ ,如需转载,请注明出处,否则将追究法律责任。