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如何保证Thread-1、2、3的顺序执行

IT图书 作者:farshow 时间:2021-09-09 09:07:17 0 删除 编辑

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有三个线程T1 T2 T3,如何保证他们按顺序执行-转载
在T2的run中,调用t1.join,让t1执行完成后再让T2执行
在T2的run中,调用t2.join,让t2执行完成后再让T3执行
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方法一:

public class Test {
    private int count=2;

    public static void main(String[] args) {
        try {
            new Test().preserveOrderViaJoin();
        }catch (Exception e){
            System.out.println("error!");
        }
    }

    private void preserveOrderViaJoin() throws InterruptedException {
        Thread tmp;
        System.out.println("start!");
        for (int i=0;i

方法二:

public void testCountDownLatch(){
        final CountDownLatch countDownLatch = new CountDownLatch(0);
        final CountDownLatch countDownLatch1 = new CountDownLatch(1);
        final CountDownLatch countDownLatch2 = new CountDownLatch(1);

        Thread thread1 = new Thread(new Runnable() {
            public void run() {
                try {
                    countDownLatch.await();
                    System.out.println(Thread.currentThread().getName()+"start");
                    System.out.println(Thread.currentThread().getName()+"end");
                    countDownLatch1.countDown();
                } catch (Exception e){
                    System.out.println(Thread.currentThread().getName()+"exception!");
                }
            }
        },"Thread-1");

        Thread thread2 = new Thread(new Runnable() {
            public void run() {
                try {
                    countDownLatch1.await();
                    System.out.println(Thread.currentThread().getName()+"start");
                    System.out.println(Thread.currentThread().getName()+"end");
                    countDownLatch2.countDown();
                } catch (Exception e){
                    System.out.println(Thread.currentThread().getName()+"exception!");
                }
            }
        },"Thread-2");

        Thread thread3 = new Thread(new Runnable() {
            public void run() {
                try {
                    countDownLatch2.await();
                    System.out.println(Thread.currentThread().getName()+"start");
                    System.out.println(Thread.currentThread().getName()+"end");
                } catch (Exception e){
                    System.out.println(Thread.currentThread().getName()+"exception!");
                }
            }
        },"Thread-3");

        thread1.start();
        thread2.start();
        thread3.start();
    }

根据网络上相应内容做出的整合

来自 “ ITPUB博客 ” ,链接:https://blog.itpub.net/1159/viewspace-2799703/ ,如需转载,请注明出处,否则将追究法律责任。

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