# ●連續質數2.3.5.7.11.13.17.19的規律●(14)

●連續質數2.3.5.7.11.13.17.19的規律●(14)
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《―》上期答案
(a+d+f)+-×÷(b+c+e+g+h)
=
(b+c=e+g)+-×÷(a+d+f+h)
=
(b+c+d+f)+-×÷(a+e+g+h)
=
(a+e+g)+-×÷(b+c+d+f+h)
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※※※
(-2-7+13)+-×÷(+3-5-11+17-19)
=
(+3-5-11+17)+-×÷(-2-7+13-19)
=
(+3-5-7+13)+-×÷(-2-11+17-19)
=
(-2-11+17)+-×÷(+3-5-7+13-19)
※※※
(4)+-×÷(-15)
=
(4)+-×÷(-15)
=
(4)+-×÷(-15)
=
(4)+-×÷(-15)
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※※※
(-2-7+13)+-×÷(+3-5-11+17+19)
=
(+3-5-11+17)+-×÷(-2-7+13+19)
=
(+3-5-7+13)+-×÷(-2-11+17+19)
=
(-2-11+17)+-×÷(+3-5-7+13+19)
※※※
(4)+-×÷(23)
=
(4)+-×÷(23)
=
(4)+-×÷(23)
=
(4)+-×÷(23)
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※※※
(+2-7+13)+-×÷(-3+5-11+17-19)
=
(-3+5-11+17)+-×÷(+2-7+13-19)
=
(-3+5-7+13)+-×÷(+2-11+17-19)
=
(+2-11+17)+-×÷(-3+5-7+13-19)
※※※
(8)+-×÷(-11)
=
(8)+-×÷(-11)
=
(8)+-×÷(-11)
=
(8)+-×÷(-11)
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※※※
(+2-7+13)+-×÷(-3+5-11+17+19)
=
(-3+5-11+17)+-×÷(+2-7+13+19)
=
(-3+5-7+13)+-×÷(+2-11+17+19)
=
(+2-11+17)+-×÷(-3+5-7+13+19)
※※※
(8)+-×÷(27)
=
(8)+-×÷(27)
=
(8)+-×÷(27)
=
(8)+-×÷(27)
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《二》今期謎題
a=?2, b=?3, c=?5, d=?7, e=?11, f=?13, g=?17, h=?19
※※※
(a+d+g)+-×÷(b+c+e+f+h)
=
(b+c+e+f)+-×÷(a+d+g+h)
=
(b+c+d+g)+-×÷(a+e+f+h)
=
(a+e+f)+-×÷(b+c+d+g+h)
※※※

?2，?3，?5，?7，?11，?13，?17，?19
※※※
(+2+7+17)+-×÷(+3+5+11+13+19)
=
(+3+5+11+13)+-×÷(+2+7+17+19)
=
(+3+5+7+17)+-×÷(+2+11+13+19)
=
(+2+11+13)+-×÷(+3+5+7+17+19)
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